Database Users

lineSetAppPriority doesn't seem to work...

For the program I posted here, I want to handle incoming calls before the default popup appears (to replace the ringtone).
Currently, my tool seems to be quick enough without lineSetAppPriority in most cases, but sadly not in all...
I was using the following code: (currently removed again, because it didn't work and even caused some troubles...)
Initialization:
Code:
if ( lineInitialize( &LineApp, theApp.m_hInstance, LineCallback,
theApp.m_pszAppName, &LineHandleCount ) == 0 )
{
LineHandles = new HLINE[LineHandleCount];
for(DWORD i = 0; i < LineHandleCount; i++)
{
if ( lineNegotiateAPIVersion( LineApp, i, 0x00010000, 0x00020000,
&ver, &extensionID ) == 0 )
{
rc = lineOpen( LineApp, i, &LineHandles[i], ver, 0, (DWORD)this,
LINECALLPRIVILEGE_MONITOR|LINECALLPRIVILEGE_OWNER,
LINEMEDIAMODE_INTERACTIVEVOICE, NULL );
if ( rc < 0 )
LineHandles[i] = NULL;
else
if ( LineHandleSignal == NULL )
LineHandleSignal = LineHandles[i];
}
}
HRESULT res = lineSetAppPriority( theApp.m_pszAppName,
LINEMEDIAMODE_INTERACTIVEVOICE,
NULL,
LINEREQUESTMODE_MAKECALL,
NULL, 1 );
}
Callback:
Code:
VOID FAR PASCAL LineCallback( DWORD hDevice,
DWORD dwMsg,
DWORD dwCallbackInstance,
DWORD dwParam1,
DWORD dwParam2,
DWORD dwParam3
)
{
if ( dwMsg == LINE_CALLSTATE )
{
LINECALLINFO *callInfo = (LINECALLINFO *)calloc(sizeof(LINECALLINFO)
+1024, 1);
callInfo->dwTotalSize = sizeof(LINECALLINFO)+1024;
lineGetCallInfo( (HCALL)hDevice, callInfo );
// different stuff...
HRESULT res;
// Remove from priority list, so lineHandoff will run the default
// call window
res = lineSetAppPriority( theApp.m_pszAppName,
LINEMEDIAMODE_INTERACTIVEVOICE, NULL,
LINEREQUESTMODE_MEDIACALL, NULL, 0 );
// Forward event to next instance (usually Windows' phone app)
lineHandoff( (HCALL)hDevice, NULL, callInfo->dwMediaMode );
// Set to top priority again
res = lineSetAppPriority( theApp.m_pszAppName,
LINEMEDIAMODE_INTERACTIVEVOICE, NULL,
LINEREQUESTMODE_MEDIACALL, NULL, 1 );
}
lineSetAppPriorty returns OK in all cases. But when a call comes in, the
default bubble applears simultaneously with the callback function. I
wanted it to be shown when I do the lineHandoff...
What am I doing wrong?
TIA,
Mirko

I used lineSetAppPriority too, with same result....
I think there is one way.....kill cprog

EDB notification

Hi All,
Is anyone familiar with the EDB notification mechanism? I have some code that has opened the appointments database to get change notifications, all well and good. The trouble is I am unable to delete the CENOTIFICATION structure, meaning I get a memory leak after every change.
if anyone has seen this or knows the solution, I'd be grateful.
Code:
CEOID apps_oid;
request= new CENOTIFYREQUEST; // or (CENOTIFYREQUEST *) LocalAlloc (LPTR,
// sizeof (CENOTIFYREQUEST));
if (request) {
request->dwSize = sizeof (CENOTIFYREQUEST);
request->hwnd = hwnd;
request->hHeap = NULL;
request->dwFlags = CEDB_EXNOTIFICATION;
request->dwParam = param;
database = CeOpenDatabaseInSession ( NULL,
&pim_guid,
&apps_oid,
L"Appointments Database",
0,
0, // or CEDB_AUTOINCREMENT,
request);
}
. . .
case WM_DBNOTIFICATION:
{
CENOTIFICATION * notification = (CENOTIFICATION *)lParam;
// Always returns FALSE
BOOL hr = CeFreeNotification(request, notification);
// Always returns 5 - access denied
DWORD dw = GetLastError();
}
break;

Send an image over HTTP in C#

Hey all
I have the following function to generate the http headers for a GET request on an image file:
Code:
byte [] headersAndImage()
{
StringBuilder s = new StringBuilder();
s.Append("HTTP/1.1 200 OK\r\n");
s.Append("Date: Tue, 17 Aug 2010 11:40:00 GMT\r\n");
s.Append("Vary: *\r\n");
s.Append("Server: Custommade\r\n");
s.Append("Content-Type: image/jpeg\r\n");
Bitmap b = new Bitmap("\\dog.jpg");
MemoryStream ms = new MemoryStream();
b.Save(ms, ImageFormat.Jpeg );
byte[] bitmapData = ms.ToArray();
ms.Close();
s.Append("Content-Length: " + bitmapData.Length + "\r\n\r\n");
byte[] headers = Encoding.ASCII.GetBytes(s.ToString());
return join(headers,bitmapData);
}
however when a browser receives this http packet the image is never displayed, usually just see the red X.
Any ideas why this won't work?

Here is the code that works for me:
Code:
public void TransmitFile(byte[] file, string fileName)
{
MemoryStream fileStream = new MemoryStream();
fileStream.Write(file, 0, file.Length);
fileStream.Position = 0;
var response = HttpContext.Current.Response;
response.Clear();
response.ClearContent();
response.ClearHeaders();
response.ContentType = @"application/force-download\n";
response.AppendHeader(@"Content-Disposition",
String.Format(@"attachment;filename=""{0}""", fileName));
long bytesToGo;
int bytesRead;
Byte[] buffer = new byte[1048576]; //1 MB buffer, you may want to use whatever fits your environment
bytesToGo = fileStream.Length;
while (bytesToGo > 0)
{
if (response.IsClientConnected)
{
bytesRead = fileStream.Read(buffer, 0, 1048576);
response.OutputStream.Write(buffer, 0, bytesRead);
response.Flush();
bytesToGo -= bytesRead;
if (bytesRead == 0)
{
break; ;
}
}
else
{
bytesToGo = -1;
}
}
fileStream.Close();
response.Flush();
response.End();
}

[Q] How to convert extended ASCII character to number in Android?

Hi!
Can you help me, please? I'm working on an Android app. I get some characters from a file on the Internet and put it to a TextView. These characters are ASCII characters. Then I read these characters one by one and convert it to numbers with the following code:
Code:
char my_char2;
char my_char3;
int myNum = 0;
for (int k = 170; k < len; k++) {
if (c.charAt(k) == '0' && c.charAt(k+1) == '.') {
my_char2 = c.charAt(k+13);
my_char3 = c.charAt(k+14);
myNum = my_char2 * 256 + my_char3;
}
}
Then I write it to an another TextView:
Code:
crlNumber.setText("" + myNum);
The problem is that this can only convert standard ASCII characters(from 0 to 127) except of the new line character(character number 10), carriage return character(character number 13) and the cancel character(character number 24).
But I need to convert also the extended ASCII characters(from 128 to 255) and the 3 characters mentioned above.
What should I do?
Thanks for helping.

Do these help?
http://stackoverflow.com/questions/13826781/java-extended-ascii-table-usage
http://stackoverflow.com/questions/5535988/string-to-binary-and-vice-versa-extended-ascii

nikwen said:
Do these help?
http://stackoverflow.com/questions/13826781/java-extended-ascii-table-usage
http://stackoverflow.com/questions/5535988/string-to-binary-and-vice-versa-extended-ascii
Click to expand...
Click to collapse
A little. I have tried the following code below. It didn't show me the number of the extended ascii characters. But I think I should somehow read the text not as a String, but as a byte, and then I think, it should work(maybe I am wrong). If it is right, please, can you tell me, how should I do it?
Code:
final String textSource = "path to my file";
URL textUrl;
try {
textUrl = new URL(textSource);
BufferedReader bufferReader = new BufferedReader(
new InputStreamReader(textUrl.openStream()));
String StringBuffer;
String stringText = "";
while ((StringBuffer = bufferReader.readLine()) != null) {
stringText += StringBuffer;
}
bufferReader.close();
textMsg.setText(stringText);
String PT = textMsg.getText().toString();
CharSequence c = new String(PT);
String string0 = "";
String string1 = "";
char my_char2;
char my_char3;
String binary = "";
String binary2 = "";
int myNum2 = 0;
int decimalValue1 = 0;
int decimalValue2 = 0;
for (int k = 170; k < len; k++) {
if (c.charAt(k) == '0' && c.charAt(k+1) == '.') {
my_char2 = c.charAt(k+13);
my_char3 = c.charAt(k+14);
string0 = Character.toString(my_char2);
string1 = Character.toString(my_char3);
char[] buffer = string0.toCharArray();
byte[] b = new byte[buffer.length];
for (int i = 0; i < b.length; i++) {
b[i] = (byte) buffer[i];
binary = Integer,toBinaryString(b[i] & 0xFF);
decimalValue1 = Integer.parseInt(binary, 2);
}
char[] buffer2 = string1.toCharArray();
byte[] b2 = new byte[buffer2.length];
for (int i = 0; i < b2.length; i++) {
b2[i] = (byte) buffer2[i];
binary2 = Integer.toBinaryString(b2[i] & 0xFF);
decimalValue2 = Integer.parseInt(binary2, 2);
}
myNum2 = decimalValue1 * 256 + decimalValue2;
}
}
crlNumber.setText("" + binary2 + "," + decimalValue1 + "," + decimalValue2 + "," + myNum2);
}

adamhala007 said:
A little. I have tried the following code below. It didn't show me the number of the extended ascii characters. But I think I should somehow read the text not as a String, but as a byte, and then I think, it should work(maybe I am wrong). If it is right, please, can you tell me, how should I do it?
Code:
final String textSource = "path to my file";
URL textUrl;
try {
textUrl = new URL(textSource);
BufferedReader bufferReader = new BufferedReader(
new InputStreamReader(textUrl.openStream()));
String StringBuffer;
String stringText = "";
while ((StringBuffer = bufferReader.readLine()) != null) {
stringText += StringBuffer;
}
bufferReader.close();
textMsg.setText(stringText);
String PT = textMsg.getText().toString();
CharSequence c = new String(PT);
String string0 = "";
String string1 = "";
char my_char2;
char my_char3;
String binary = "";
String binary2 = "";
int myNum2 = 0;
int decimalValue1 = 0;
int decimalValue2 = 0;
for (int k = 170; k < len; k++) {
if (c.charAt(k) == '0' && c.charAt(k+1) == '.') {
my_char2 = c.charAt(k+13);
my_char3 = c.charAt(k+14);
string0 = Character.toString(my_char2);
string1 = Character.toString(my_char3);
char[] buffer = string0.toCharArray();
byte[] b = new byte[buffer.length];
for (int i = 0; i < b.length; i++) {
b[i] = (byte) buffer[i];
binary = Integer,toBinaryString(b[i] & 0xFF);
decimalValue1 = Integer.parseInt(binary, 2);
}
char[] buffer2 = string1.toCharArray();
byte[] b2 = new byte[buffer2.length];
for (int i = 0; i < b2.length; i++) {
b2[i] = (byte) buffer2[i];
binary2 = Integer.toBinaryString(b2[i] & 0xFF);
decimalValue2 = Integer.parseInt(binary2, 2);
}
myNum2 = decimalValue1 * 256 + decimalValue2;
}
}
crlNumber.setText("" + binary2 + "," + decimalValue1 + "," + decimalValue2 + "," + myNum2);
}
Click to expand...
Click to collapse
Hm, I don't know. According to this answer, you can change the encoding on the desktop, otherwise you will just see question marks.
But according to the accepted answer here, this should be done automatically on a Linux system. And Android is Linux based. Did you try it on an Android device or just on your computer?
Bytes shouldn't work. In Java they are signed, so their range is -128 ... 127.

nikwen said:
Hm, I don't know. According to this answer, you can change the encoding on the desktop, otherwise you will just see question marks.
But according to the accepted answer here, this should be done automatically on a Linux system. And Android is Linux based. Did you try it on an Android device or just on your computer?
Bytes shouldn't work. In Java they are signed, so their range is -128 ... 127.
Click to expand...
Click to collapse
Yes, I tried it on my Android device. Maybe, the best choice would be then to use that certificate code which you suggested me in one of my previous threads, but the problem is, that I am beginner in Android developing and I read it and I didn't know how to use it in my code. So I thougt, if I got the 2 ASCII characters and converted it to decimal numbers, it would also work. And it also works until I have the standard ASCII characters. When there is an extended ASCII character, it shows me the number 65533.

adamhala007 said:
Yes, I tried it on my Android device. Maybe, the best choice would be then to use that certificate code which you suggested me in one of my previous threads, but the problem is, that I am beginner in Android developing and I read it and I didn't know how to use it in my code. So I thougt, if I got the 2 ASCII characters and converted it to decimal numbers, it would also work. And it also works until I have the standard ASCII characters. When there is an extended ASCII character, it shows me the number 65533.
Click to expand...
Click to collapse
But I think I have found out something.
Code:
string0 = Character.toString(my_char2);
string1 = Character.toString(my_char3);
int one = 0;
int two = 0;
String ascii1="\u001f";
String ascii2="\u0018";
String aa = "";
String bb = "";
if(string0.equals(ascii1)){
one = one + 31;
aa = aa + one;
}else{
one = 1;
}
if(string1.equals(ascii2)){
two = two + 24;
bb = bb + two;
}else{
two = 1;
}
textPrompt.setText("" + aa + bb);
But this needs a little correction, because this way it doesn't show me anything, but if I write
Code:
textPrompt.setText("" + aa);
inside my first if statement it shows me correctly 31. What can be the mistake I have made?

convert ASCII character
I'm a self android learner. I want to convert ascii code to character. Here is the code I used.
String s = "1000001";
int num = Integer.parseInt(s, 2);
TextView textView = new TextView(this);
textView.setText(String.valueOf(num));
setContentView(textView);
Here s is 1000001(65 in decimal) 65 is ascii value of 'A'. I want to get 'A' in my output screen.variable num has the value 65. please help me

My JSONArray keeps appending the last object on loop

Here is my code:
Code:
if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);
JSONObject jObject = new JSONObject(jsonObj.toString().trim());
Iterator<?> keys = jObject.keys();
JSONArray temp_json_arr = null;
JSONObject temp_json_obj = null;
String temp_string = "";
int index_count = 0;
LinearLayout ll = (LinearLayout)findViewById(R.id.test_layout);
//temp_json_obj = jsonObj.getJSONObject("identification");
//Log.d("TEST: ", "ARRAY LENGTH> "+temp_json_arr.length());
while( keys.hasNext() ){
String key = (String)keys.next();
Log.d("TEST: ", "KEYS> " + key);
// Getting JSON Array node
temp_json_arr = jsonObj.getJSONArray(key);
// looping through All Questions
for (int i = 0; i < temp_json_arr.length(); i++) {
JSONObject q = temp_json_arr.getJSONObject(i);
if( key.equals("identification") ) {
tv[tv_ctr] = new TextView(getApplicationContext());
tv[tv_ctr] = (TextView)findViewById(id);
id++;
et[identification_question] = new EditText(getApplicationContext());
et[identification_question] = (EditText)findViewById(id);
id++;
//json manipulation
try {
jsonOb.put("question-id", tv[tv_ctr].getText().toString());
jsonOb.put("answer", et[identification_question].getText().toString());
} catch(Exception e) {
}
Log.d("TEST: ", "jsonOb> " + jsonOb.toString());
//answer += et[identification_question].getText().toString() + "-" + tv[tv_ctr].getText().toString() + "/";
tv_ctr++;
identification_question++;
jsonArr.put(test,jsonOb);
test++;
Log.d("TEST: ", "jsonArr> " + jsonArr.toString());
}
Everytime I use .put of the JSONArray, it appends the last object on all indexes for example:
I have 3 input namely answer 1 , answer 2 and answer 3
The expected json data will be this:
Code:
[{"answer":"answer1","question-id":"question1"},{"answer":"answer2","question-id":"question2"},{"answer":"answer3","question-id":"question3"}]
But this is the current output:
Code:
[{"answer":"answer3","question-id":"question3"},{"answer":"answer3","question-id":"question3"},{"answer":"answer3","question-id":"question3"}]
As you can see the last index get appended multiple times.

Nevermind I've already solved my own problem.